Justin Dolske’s blog

The Conversation {7 comments}

1. Alex {Thursday June 5, 2008 @ 5:25 pm}

   (average smuggler doing the kessel run) / (han solo) = 18 parsecs / 12 parsecs

   average smuggler = 1.5 han solos

2. Neil {Friday June 6, 2008 @ 12:52 am}

   No sticks of butter?

3. Gervase Markham {Friday June 6, 2008 @ 12:55 am}

   Neil: never fear, here you are:

   1 parsec per keg = 1.23700182 × 10^13 rods per US sticks of butter

   Gerv

4. Manny {Friday June 6, 2008 @ 2:33 am}

   Try Planck’s constant in calories fortnight

5. Madhava {Friday June 6, 2008 @ 7:05 am}

   Nicely calculated, sir. A keg of butter to you.

6. zack {Friday June 6, 2008 @ 8:14 pm}

   now that’s fuel efficiency!

7. hasdruabl {Sunday June 29, 2008 @ 3:56 am}

   Hey …

   How did you make the vista throbber (long time ago ^^)? Could you send me or post the JavaScript for APNGedit?

   fox_qjnzry@trashmail.net

   thx

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